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vaieri [72.5K]
3 years ago
9

Nots sure, I need help

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer: OPTION C.

Step-by-step explanation:

For this exercise it is important to remember the the following properties:

1. The Produtct of Powers Property states that:

(a^m)(a^n)=a^{(m+n)}

2. The Quotient of Powers Property states that:

\frac{a^m}{a^n}=a^{(m-n)}

Therefore, given the following expression:

\frac{5^a*5^5}{5^b}

You can simplify it by applying the properties explained before.

So, you get that following expression:

\frac{5^a*5^5}{5^b}=\frac{5^{(a+5)}}{5^b}=5^{(a+5)-b}=5^{(a+5-b)}

Then, you can determine that  Clifton is correct.

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In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
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Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

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Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

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