Answer:
Step-by-step explanation:
we know that
The phrase "Three times the quantity five less than x" means 3 multiplied by the difference of x minus 5
3(x-5)
The phrase "the product of six and x" means the number 6 multiplied by x
6x
therefore
The phrase" Three times the quantity five less than x, divided by the product of six and x" is equal to the quotient of 3(x-5) and 6x
Answer:
cost per mile = $2.
Step-by-step explanation:
Given the cost function, c(m) = 2m + 4,
Where the m represents the number of miles traveled, and $2 is the cost per mile of the cab. The $4 represents the flat rate, a set fee, or the initial value.
Therefore, the cost per mile of the cab is $2.
I'll go with A and B
Hope this helps
Answer:
D
Step-by-step explanation:
You have to have exactly the same thing underneath the radical. So for example in choice A you have sqrt(2) and sqrt(3) underneath the radical. They are not the same. Choice A is not the answer.
Choice B has the same problem sqrt(5) is not the same thing as sqrt(3) and choice B is not the answer.
Choice C has sqrt(5) and sqrt(6) as your choice. They are not the same. C is not correct.
D is the answer. Both choices have sqrt(7) as the radicals. They are both 7. They are the same.
For polar form you need to find the modulus (length of the vector) and the argument (angle of the vector) and present in form rcis(Arg) or re^Argi
start with the modulus r=sqrt(a^2 +b^2)
=sqrt(-2^2 +2^2)
= sqrt(4+4)
=sqrt(8)
=2sqrt(2)
next the argument, firstly arg=tan(b/a)
= tan(2/2)
=tan(1)
=pi/4 . (exact values table)
Now consider the quadrant the complex number is in, as it is (-2,2) it is in the second quadrant and as such your Arg value is:
Arg=pi-arg
= pi-pi/4
= 3pi/4
add it all together and your complex number in polar form is:
2sqrt2cis(3pi/4)
note: cis is short hand for cos(x)+isin(x), it is possible your tutor would rather you use the complex exponential form which is simply re^Argi and your answer would look like:
2sqrt2e^(3pi/4)i
Also notice the difference between arg and Arg as this often slips students up and always present Arg in prinicple argument form ie -pi<Arg<pi
Hopefully this has been clear enough and good luck
