The answer is A
A. The pre-image will be congruent to the image.
If you use the first answer, the equation becomes 2x + 2y = 16. You could subtract this from equation Q to eliminate x.
The second answer makes equation P -2x - 2y = -16. You could add this to equation Q to eliminate x. You can use both of these methods to eliminate the x term, but if you can only choose one, you should choose the second option.
BY USING MIDDLE TERM SPLITTING,
3y^2-(3y-2y)-2
(3y^2-3y)+(2y-2)
3y(y-1)+2(y-1)
(3y+2)(y-1)
HOPE THIS WILL HELP U
Answer:
False
Step-by-step explanation:
Well to solve for z we single it out, distribute, use the communicative property, and combine like terms.
42 = -7(z - 3)42 = -7(z - 3)
Distribute
42 = -7z + 21*42 = -7z + 21
42 = -7z + 882 = -7z + 21
-42 to both sides
-7z + 840 = -7z + 21
-21 to both sides
-7z + 819 = -7z
+7z to both sides
819 = 0
<em>Thus, </em>
<em>the given equation is false.</em>
<em>I hope this helps :)</em>
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
