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Lorico [155]
3 years ago
14

Use a half-angle identity to find the exact value of tan 22.5°.

Mathematics
2 answers:
Stells [14]3 years ago
6 0

Answer:

[C]  tan22.5 = \sqrt{2} - 1

dusya [7]3 years ago
3 0

Answer:

\sqrt{2} -1

Step-by-step explanation:

22.5 degrees is half of 45 degrees (special angle for which we know exactly the value of all three basic trigonometric functions (sine, cosine, and tangent).

So we start recalling the formula for tangent of a half angle: tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }

We need just the values of:

sin(\alpha )=sin(45^o)=\frac{\sqrt{2} }{2}

and of

cos(\alpha )=cos(45^o)=\frac{\sqrt{2} }{2}

to answer the question. Then, we use those values in the original formula for tangent of a half angle:

tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }\\tan(22.5^o)=\frac{1-\frac{\sqrt{2} }{2} }{\frac{\sqrt{2} }{2}} =\frac{2-\sqrt{2} }{\sqrt{2} } =\frac{2\sqrt{2}-2 }{2} =\sqrt{2} -1

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3 years ago
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2 years ago
A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?
Ugo [173]

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

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Let the density of the gold sample be represented by ρ

The formula for the density is:

Density = \frac{Mass}{Volume}

\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3

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Learn more here: brainly.com/question/17780219

3 0
3 years ago
What is the range of this relation?
VARVARA [1.3K]

Answer:

Domain = {-5,2,4,6,8,9), range = (-3,-1,0,4,6,7}

Step-by-step explanation:

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The domain is the input and the range is the output

domain is { 2,8,-5,4,6,9} and the range is {4,-3,-1,6,7,0}

We put the numbers in order from smallest to largest

Domain = {-5,2,4,6,8,9), range = (-3,-1,0,4,6,7}

5 0
3 years ago
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saw5 [17]
The answer is correct because it would have to go like this;

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7 0
3 years ago
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