Answer:
3.1 ns ; 1.25 ; 3.097
Explanation:
Given :
IF, 3 ns;
ID, 2.5 ns;
EX, 2 ns;
MEM, 3 ns;
WB, 1.5 ns.
Use 0.1 ns for the pipelineregisterdelay
maximum time required for MEM = 3 ns
Pipeline register delay = 0.1 ns.
Clock cycled time of the pipelined machine= maximum time required + delay
3ns+0.1 ns = 3.1 ns
2.) for stall after every 4 instruction :
CPI of new machine :
(1 + (1 /4)) = 1 + 0.25 = 1.25
3.)
The speedup of pipelined machine over the single-cycle machine is given by :
Average time per instruction of single cycle ÷ average time per instruction of pipelined
Clock time of original machine = 12ns
Ideal CP1 = 1
CPI of new machine = 1.25
Clock period = 3.1 ns
(12 * 1) / (1.25 * 3.1) = 12 / 3.875
= 3.097
D. Speed up will equal the number of stages in the machine
Answer:
Items placed in a Web store's shopping cart for future purchase during the anonymous browsing session will not be saved on the user's computer
Explanation:
Browsing ananymously implemented as In-private browsing by some web browsers allows you to browse without leaving histories and cookies, however your activities can still be monitored by an admin and you are not protected from malware because of in-private browsing. Because browsing histories are not saved, any data from a web store such as future purchase intention will also not be saved
either in the doc its self or in the attachment file
Answer:
There is a wide application of kinematics; it is also used in astrophysics. In mechanical engineering, robotics, and biomechanics, it is used to describe the motion of the system of the joint parts.
