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3 years ago

Let f(x) = 4x-5 and g(x) = 3x, find (f/g)(x). Do not simplify.

Mathematics

1 answer:

masha68 [24]3 years ago

4 0

Answer:

(f/g)(x) = f(x)/g(x) = [4x-5]/[3x]

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A rectangular sticker has an area of 50 square centimeters. Its perimeter is 30 centimeters. What are the dimensions of the stic

Nata [24]

Length + width = 1/2 the perimeter:30/2 = 15

Area = length x width

List the factors of 50: 1, 2, 5, 10, 25, 50.

Find the two factors that when added together equal 15:

Dimensions are 5 cm by 10 cm.

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2 years ago

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House is 50.0 ft long and 26 ft wide and has 8.0-ft- m high ceilings. what is the volume of the interior of the house in cubic m

Tom [10]

560 cm to the power of 2

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3 years ago

A collection of stamps consists of 22¢ stamps and 40¢ stamps. The number of 22¢ stamps is three more than four times the number

Artemon [7]

Answer:

Step-by-step explanation:

Let :

Number of 40¢ = x

Number of 22¢ = 4x + 3

Total stamp value = $8.34 = (8.34 * 100) = 834¢

40¢x + 22¢(4x + 3) = 834¢

40x + 88x + 66 = 834

128x = 834 - 66

128x = 768

x = 768 / 128

x = 6

Number of 22¢ stamp:

4(6) + 3 = 24 + 3 = 27

7 0

3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

2 years ago

Please help its urgent Proof

LuckyWell [14K]

Answer:

yes because of a postulate or a theorem

Step-by-step explanation:

7 0

2 years ago