A
using the Cosine rule in ΔSTU
let t = SU, s = TU and u = ST, then
t² = u² + s² - (2us cos T )
substitute the appropriate values into the formula
t² = 5² + 9² - (2 × 5 × 9 × cos68° )
= 25 + 81 - 90cos68°
= 106 - 33.71 = 72.29
⇒ t = ≈ 8.5 in → A
A runner runs at an average speed of 5 m/s for 50 seconds. How far did the runner run in metres?
2 answers:
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Answer:
<em>The shaded region has an area of 1400 square units</em>
Step-by-step explanation:
<u>Area of Compound Shapes</u>
We are given a shape and it's required to calculate its area. The shape can be divided into three rectangles as shown in the figure attached below.
The lengths of these rectangles are x, y, and z.
The value of x can be calculated as:
x = 60 - 15 - 10 = 35
Similarly:
y = 60 - 15 = 45
z = y = 45
The first rectangle has dimensions of x by 10, thus its area is:
A1 = 35*10 = 350
The second rectangle has dimensions of 60 by 10:
A2 = 60*10 = 600
The third rectangle has dimensions y by 10:
A3 = 55*10 = 450
The shaded area is:
A = 350 + 600 + 450 = 1400
The shaded region has an area of 1400 square units
Answer:
x = 13
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = h (b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
Here A = 55, h = 5. b₁ = x, b₂ = 9, then
× 5 × (x + 9) = 55
2.5(x + 9) = 55 ( divide both sides by 2.5 )
x + 9 = 22 ( subtract 9 from both sides )
x = 13