Y = 15(6) + 25
If you need me to elaborate on that please ask! Here to help :)
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
Answer:
The equation of a line that runs through (-6,2) and is parallel to a line with a slope of (-1/4) is x + 4y - 2 = 0
Step-by-step explanation:
Slope of the parallel equation is m 1 = (-1/4)
<em>If the two liner are parallel the, slope of both lines are equal.</em>
⇒The slope of the equation of line = m2 = m1 = -(1/4)
The point (x0, y0) = (-6,2)
Now, by THE POINT SLOPE FORMULA: The equation of a line is given as
( y - y0) = m (x -x0)
Now, here the equation of line is given as:

or, 4y - 8 + x + 6 = 0
or, x + 4y - 2 = 0
Hence, the required line equation is x + 4y - 2 = 0
Answer:
the answer is 9.6 cm
Step-by-step explanation:
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