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vekshin1
3 years ago
6

-6 (-2/3) How is it solved

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

Answer:

4

Step-by-step explanation:

-6 × (-2/3)

-2 × (-2)

= 4

hope it helpful

Mars2501 [29]3 years ago
5 0
You multiply -6 and -2/3. Which is 4
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Someone please help me it's worth 35 points
Zigmanuir [339]
Question 1)
I assume it asks about the circumference (of only the circle arc)
C=r*2*pi
r=2
-> C=4pi

1 Quarter only of the circle: C/4=pi=3.1

if it's the perimeter of the shape then you need to add the two 2in sides

C=3.1+2*2=7.1

2)
C=r*2*pi, but not a full circle, only semi-> divide by 2-> C=r*pi
r=30
C=30pi=94.2

3)
the radius of the semicircle is 6/2=3mm
semicircle C=r*pi=3pi

add the rectangle perimeter
3pi+2*3+6=12+3pi=21.4

4)
C=2r*pi
insert 2r=d=12
C=12pi=37.7

5)
C=2r*pi
r=10
C=20*pi~62.8

3 rotations of the wheel->
distance=C*3=188.4
4 0
3 years ago
The function f(x) = (x − 4)(x − 2) is shown.
Trava [24]

Answer:

Last Option : all real numbers greater than or equal to −1

Step-by-step explanation:

8 0
3 years ago
Bruce sees 29 oak trees and 4 maple trees. Then he sees double the number of pine trees as maple trees. How many trees does he s
Anit [1.1K]
29 + 4 + ? = ?
29 × 2 = 58
58 + 4 = 62
62 + 29 = 91
? = 58
? = 91
29 + 4 + 58 = 91
7 0
4 years ago
on the grid below, draw and label an aquarium shaped like a rectangular prism with a volume of 8,000 cubic inches. (Hint: A cube
n200080 [17]
If you want an aquarium in shape of a cube with volume of 8000, then use the formula for volume of cube to find the length of one side:
V = s^3
where
s = side length
Substitute,
8000 = s^3
s = cuberoot(8000)
s = 20 inches

Well, if you have to draw this on a graphing paper, you should first make a scale to fit the drawing, like 1 inch = 0.5 cm, so a side length of 20 inches is equivalent to 10 cm on your graphing paper.

Hope this helped!
3 0
4 years ago
1+1 is what because I’m really confused on this question and answer is it...idk 4
sergiy2304 [10]

Answer:

2

Step-by-step explanation:

1+1=2

5 0
3 years ago
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