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vekshin1
2 years ago
6

-6 (-2/3) How is it solved

Mathematics
2 answers:
Tresset [83]2 years ago
8 0

Answer:

4

Step-by-step explanation:

-6 × (-2/3)

-2 × (-2)

= 4

hope it helpful

Mars2501 [29]2 years ago
5 0
You multiply -6 and -2/3. Which is 4
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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
Rotundo to the nearest 10 of 569
Brums [2.3K]
569 rounded to the nearest 10 would be 570.
The 6 is your 10's place and anything after it (aka the 9) that is equal to or greater than 5 makes your next number go up one
3 0
3 years ago
Read 2 more answers
What number is halfway between .2 and .3
Ghella [55]

Answer:

.201

Step-by-step explanation:

3 0
2 years ago
Tom has 2 feet of wire. He uses of the wire to hang a picture. How much wire did he use to hang the picture?
Ipatiy [6.2K]

Answer:

D.  1  1/2 feet

Step-by-step explanation:

<u>Multiply the numbers to find the length of wire used.</u>

  • 2 1/2 × 3/5 =
  • 5/2 × 3/5 =
  • 3/2 =
  • 1 1/2 feet

Correct choice is D

3 0
2 years ago
2. Husein used a ladder to climb up a tree. The
Harman [31]
Answer:

7.28 m

Explanation:

Use the Pythagorean Theorem. The length of the ladder is the hypotenuse.

a^2 + b^2 = c^2
a = 2, b = 7, c = ?

Plug in the values into the equation.

2^2 + 7^2 = c^2
4 + 49 = c^2

Square root both sides to get c = 7.28
5 0
3 years ago
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