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Ray Of Light [21]
4 years ago
12

Please help. 15 points! Two cards are randomly chosen, one at time, from a standard deck of 52 playing cards without replacement

. What is the probability both cards will be an Ace?
Mathematics
2 answers:
Fittoniya [83]4 years ago
7 0
-- For the first draw, there are 52 cards in the deck and 4 of them are aces.
The probability of drawing an ace is (4/52) = 1/13 .

If that draw is successful, then . . .

-- For the second draw, there are 51 cards in the deck and 3 of them are aces.
The probability of drawing an ace is (3/51) = 1/17 .

-- The probability of BOTH of these events happening is

(1/13)·(1/17) = (1/221) = 0.004525...

That's about 0.45 percent.  You should not bet money on it.
lesya692 [45]4 years ago
5 0
|\Omega|=52\cdot51=2652\\
|A|=4\cdot3=12\\\\
P(A)=\dfrac{12}{2652}=\dfrac{1}{221}\approx0.5\%
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3 years ago
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3 years ago
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Lostsunrise [7]

Answer:

A. x=0

Step-by-step explanation:

x+20+10x=20+9x

cancel equal terms

x+10x+9x

add x to 10x

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4 0
3 years ago
2. What percent of rolling a 2<br><br><br> 3 probability of getting HH
faust18 [17]

<u>Answer:</u>

2. The correct answer option is 25%.

3. The experimental probability is 3% greater than the theoretical probability.

<u>Step-by-step explanation:</u>

2. We are given that a number cube is rolled 20 times out of which 5 times it lands on the number 2.

We are to find the experimental probability of getting the number 2.

P (2) = \frac{5}{20} \times 100 =\frac{1}{4} \times 100 = 25%

3. The theoretical Outcomes are: HH HT TH TT

So theoretical probability of getting HH = \frac{1}{4} \times 100 = 25%

Total number of outcomes = 28+22+34+16 = 100

So experimental probability of getting HH = \frac{28}{100} \times 100 = 28%

Therefore, the experimental probability is 3% greater than the theoretical probability.

6 0
3 years ago
If the total value of the coins is 36¢, what is the missing coin?
laiz [17]

Answer:

1 penny 3 nickels 2 dimes = 36 cents

quarter

Step-by-step explanation:

8 0
3 years ago
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