Question

How long will it take a car to go from a complete stop to 44 m/s if they are

Answer 1

Answer:

$\boxed{\sf Time \ taken \ (t) = 8.8 \ s}$

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 44 m/s

Acceleration (a) = 5 m/s²

To Find:

Time taken (t)

Explanation:

From equation of motion we have:

$\boxed{ \bold{v = u + at}}$

By substituting value of u, v & a in the equation we get:

$\sf \implies 44 = 0 + 5t \\ \\ \sf \implies 44 = 5t \\ \\ \sf \implies 5t = 44 \\ \\ \sf \implies t = \frac{44}{5} \\ \\ \sf \implies t = 8.8 \: s$