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Svetlanka [38]
3 years ago
15

For normal weight students, regular physical activity is unnecessary." True O False​

Physics
2 answers:
Mrac [35]3 years ago
8 0

Answer:

False ....Even for a normal student , in order to maintain the fitness they should exersice ...

marysya [2.9K]3 years ago
3 0

Answer:

The answer is False

Explanation:

to keep the body active and going in the good state

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Two 0.50 g spheres are charged equally and placed 2.5 cm apart. When released, they begin to accelerate at 170 m/s^2 .What is th
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Answer:

q=7.65*10^{-8}C

Explanation:

Using Newton's second law, we calculate the magnitude of the electric force between the spheres:

F=ma\\F=0.5*10^{-3}kg(170\frac{m}{s^2})\\F=0.085N

The magnitude of the charge in both spheres is the same. So, we calculate the charge, using Coulomb's law:

F=\frac{kq^2}{d^2}\\q=\sqrt\frac{Fd^2}{k}\\q=\sqrt\frac{(0.085N)(2.5*10^{-2}m)^2}{8.99*10^9\frac{N\cdot m^2}{C^2}}\\q=7.65*10^{-8}C

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What are the base units in the metric system?
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A car travels in a straight line for 5 h at a constant speed of 72 km/h. What is it’s acceleration
Luda [366]

Answer:

a \approx \: 0.001 \: m {s}^{ - 2}

Explanation:

Given:

initial \:  velocity \:  (u) = 0 \\  \\ Final  \: Velocity \:  (v) = 72 km /h   \\  \\ Time \:  (t) = 5 \:  hours \\  \\ Acceleration \:  (a) =?  \\  \\  \because \: a =  \frac{v - u}{t}  \\  \\  \therefore \: a =  \frac{72 - 0}{5}  \\  \\ a =  \frac{72}{5}  \\  \\ a = 14.5 \: km {h}^{ - 2}  \\  \\ a =  \frac{14.5 \times 1000}{3600\times 3600} \: m {s}^{ - 2}   \\  \\ a = 0.00111882716 \\  \\ a \approx \: 0.001 \: m {s}^{ - 2}

4 0
3 years ago
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