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lord [1]
3 years ago
6

Determine the volume of a rectangle box with a link of 5 inches height of 7 inches and the width of 9 inches

Mathematics
1 answer:
taurus [48]3 years ago
8 0
The answer is 315. just multiply all of the numbers.
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What is equivalent to (5x-6) (2x+3) ?
ioda
Option A, because you split the (2x + 3) into 2x and 3.
7 0
3 years ago
What is the nth term of quadratic sequence 4 7 12 19 28
Anni [7]
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:

Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².

We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.

Now we find the difference between the actual terms of the sequence and the numbers we just found:

4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.

Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
7 0
3 years ago
What is the genral form of (x-6)2+(y-4)2=56
dusya [7]
X+y=38 that’s your answer
5 0
3 years ago
A+0=0+a=0 is true except for all teal numbers except 0 true or false
jolli1 [7]

Try it with some random number, like a=3.

       Is "3+0 = 0+3 = 0" true?    No.

If you were doing multiplication, then it would be true, but not with addition.

6 0
3 years ago
Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
Leviafan [203]

Answer:

Probability of having student's score between 505 and 515 is 0.36

Given that z-scores are rounded to two decimals using Standard Normal Distribution Table

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu (Mean) = 510, SD = 10.4 we have z(x) by using z(x) = (x - Mu)/SD as under:

In our case, we have x = 505 & 515

Approach 1 using Standard Normal Distribution Table:

z for x=505: z(505) = (505-510)/10.4 gives us z(505) = -0.48

z for x=515: z(515) = (515-510)/10.4 gives us z(515) = 0.48

Afterwards using Normal Distribution Tables and rounding the values to two decimals we find the probabilities as under:

P(505) using z(505) = 0.32

Similarly we have:

P(515) using z(515) = 0.68

Now we may find the probability of student's score between 505 and 515 using:

P(505 < x < 515) = P(515)-P(505) = 0.68 - 0.32 = 0.36

PS: The standard normal distribution table is being attached for reference.

Approach 2 using Excel or Google Sheets:

P(x) = norm.dist(x,Mean,SD,Commutative)

P(505) = norm.dist(505,510,10.4,1)

P(515) = norm.dist(515,510,10.4,1)

Probability of student's score between 505 and 515= P(515) - P(505) = 0.36

Download pdf
6 0
3 years ago
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