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AfilCa [17]
2 years ago
13

Which equation matches the relationship shown in the table

Mathematics
1 answer:
Marysya12 [62]2 years ago
7 0

Answer:

it is the second answer check that answer I'm pretty sure its correct

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COOKING Franklin is cooking a 3-pound turkey breast for 6 people. If the number of pounds of turkey varies directly with the num
Gwar [14]

<u>Answer-</u>

2, 4, and 8 people will need 1, 2, 4 pounds of turkey respectively.

<u>Solution-</u>

Given in the question, number of pounds of turkey varies directly with the number of people, i.e as the number of people increases or decreases, the pound of turkey also increases or decreases.  

Taking,

x = number of people,

y = pounds of turkey.

This condition can be represented as,

\Rightarrow y\ \alpha \ x\\\Rightarrow y=kx

As given in the question, when x = 6 y = 3

\Rightarrow 3=k\times 6

\Rightarrow k=\frac{3}{6}= \frac{1}{2}

Now, putting the values of k in the equation, the equation becomes

\Rightarrow y=\frac{1}{2}x

Now, we can get the values of y or number of pounds of turkey needed by putting the given x or number of people.

All the calculations are shown in the attached table.


5 0
3 years ago
2. JENNIFER IS TRYING TO SAVE MONEY. SHE WILL TAKE $150.00 TO
lisov135 [29]

Hope this helps.

If not, go to: https://www.mathportal.org/calculators/financial-calculators/simple-interest-calculator.php

6 0
3 years ago
What are solutions for the equation y=8x-5
Semmy [17]

Answer:

Multiple

Step-by-step explanation:

You put the equation in slope intercept form, therefore, the solutions are the entire line!

Every point on the line can be considered a solution.

4 0
3 years ago
How do u multiply exponents
Ymorist [56]
So, by multiplying the exponents, you would add all of the square roots together. For example for your question you would add 1+1+4+5=11 so the answer is c to the power of 11
4 0
3 years ago
Read 2 more answers
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
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