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snow_lady [41]
3 years ago
13

PLEASE HELP! WILL GIVE 20 POINTS! 2. The Children’s Hospital sponsors a 10 K rac e to raise money. It receives $7 5 per race ent

ry and $10,000 in donations , but it must spend $2 5 per race entry to cover the cost of the race. Write and solve an inequality to determine the number of race entries the ch arity needs to raise at least $100 ,000
Mathematics
1 answer:
Kazeer [188]3 years ago
6 0
You need 1800 participants to raise at least $100,000
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What is the distance ab rounded to the nearest tenth when a=(-1,2) and b=(1,-2). ​
Tom [10]

Answer:

it gives you the formula, so all you have to do is plug in the coordinates

Step-by-step explanation:

7 0
2 years ago
What is half of the fraction 3/4
schepotkina [342]
The half of 3/4 is 0.375, or 3/8. All you have to do is multiply 3/4 times 1/2. 
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3 years ago
Can someone please help me with this question?
sattari [20]
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7 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
2 years ago
PLEASE ANSWER DONT IGNORE ): I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS
Lera25 [3.4K]

Answer:

Niether of them are correct

Step-by-step explanation:

If you actually put into your calculator 2^28, it equals 268,435,456. This is because you're not just squaring 28, you are multiplying 2 by 2-- 38 times. This will quickly add up, even if you start out with 2 it will create a very large number.

7 0
2 years ago
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