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Gnoma [55]
3 years ago
13

Which line from "On Becoming an Inventor" supports the idea that Dean's time at Worcester Polytechnic Institute was very useful

to him even if he did not graduate?
Engineering
2 answers:
Andreyy893 years ago
4 0

Answer:

The answer is, option B. I found that at college I could get help from my teachers with solving business problems and in learning new techniques for designing new things.

Explanation:

Stolb23 [73]3 years ago
3 0

Answer:

Explanation:

The line from "On becoming an inventor" that says:

"I found that at college I could get help from my teachers with solving business problems and in learning new techniques for designing new things"

On Becoming an Inventor was by Dean Kamen an American Engineer, Inventor and Businessman

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What are the benefits of using the engineering design process? combining scientific knowledge and creativity in a rigid and stru
Trava [24]

Answer:

combining scientific knowledge, careful reasoning, and artistic invention in a flexible approach to problem-solving

Explanation:

7 0
3 years ago
What makes building an airplane while flying so difficult?
Naddik [55]

Answer: Because if something goes wrong while you are flying it it will crash

Explanation:

7 0
2 years ago
Imagine the reaction A + B LaTeX: \Longleftrightarrow⟺ C + D proceeds at room temperature (25 °C) and is determined to have a re
Wittaler [7]

Answer:

0.2 kcal/mol is the value of \Delta G for this reaction.

Explanation:

The formula used for is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q

\Delta G^o=-RT\ln K

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy  

R =Universal  gas constant

T = temperature

Q = reaction quotient

k = Equilibrium constant

We have :

Reaction quotient of the reaction = Q = 46

Equilibrium constant of reaction = K = 35

Temperature of reaction = T = 25°C = 25 + 273 K = 298 K

R = 1.987 cal/K mol

\Delta G_{rxn}=-RT\ln K+RT\ln Q

=-1.987 cal/K mol\times 298 K\ln [35]+1.987 cal/K mol\times 298K\times \ln [46]

=-2,105.21 cal/mol+2,267.04 cal/mol=161.82 cal/mol=0.16182 kcal/mol\approx 0.2 kcal/mol

1 cal = 0.001 kcal

0.2 kcal/mol is the value of \Delta G for this reaction.

5 0
3 years ago
A body of weight 300N is lying rough
kumpel [21]

Answer:

Horizontal force = 89.2 N

Explanation:

The frictional force = coefficient of friction * magnitude of the force (weight of the body) * cos theta

Substituting the given values, we get -

Frictional Force = 0.3*300 * cos 25 = 89.2 N

Horizontal force = 89.2 N

6 0
2 years ago
Select three ways an engineer can create a view of a design.
Angelina_Jolie [31]

Sketching projection

  • Sketching will give the brief planning of the engineering work to be done so it's important

Isometric projection

  • Yes doing a work in 3D factor out the mistakes which can be optimised

Third angle projection:-

  • Viewing angles matter a lot
  • So it will help the engineer to make it perfect from all angles
5 0
2 years ago
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