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3 years ago

What are the four categories of engineering materials used in manufacturing?

Engineering

1 answer:

alexgriva [62]3 years ago

8 0

Answer:

metals, composite, ceramics and polymers.

Explanation:

The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.

i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.

ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.

iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.

iv) Polymers: They have low weight and are poor conductors of electricity and heat

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Nitrogen at an initial state of 300 K, 150 kPa and 0.2 m3 is compressed slowly in an isothermal process to a final pressure of 8

s344n2d4d5 [400]

Answer:

Work = - 4175.23 J

Heat Transfer = -4175.23 J

Explanation:

The work done in an isothermal process, is given by the following formula:

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3 years ago

Read 2 more answers

What is the purpose of the graphic language?

solmaris [256]

Answer:

enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.

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3 years ago

Technician A says that for any fuel to burn efficiently, it must be vaporized and fully mixed with the proper amount of air. Tec

Ira Lisetskai [31]

Both technicians are correct

Explanation:

They are each correct for separate reasons. Tech A is correct due to pressure and temperature both being important factors and quantities to vaporize anything. Tech B is correct due to fuel particles being easier to burn due to their chemical structure.

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2 years ago

Calculate the diameter of pneumatic cylinder to drive a mechanism. The force exerted by the mechanism is 80 N. The return force

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Answer:

14.27 mm

Explanation:

Force = 80 Newton

Pressure exerted = 5 bar = 5×10⁵ Pa

Pressure exerted = Force/Area

Area = Force/Pressure

$Area=\frac{80}{500000}\\\Rightarrow Area=0.00016\ m^2$

Area of the cylinder=πd²/4

$\Rightarrow \frac{\pi}{4}d^2=0.00016\\\Rightarrow d^2=\frac{4\times 0.00016}{\pi}\\\Rightarrow d^2=0.0002037\\\Rightarrow d=0.01427\ m$

Hence diameter of cylinder 14.27 mm

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3 years ago