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Kaylis [27]
2 years ago
5

A body of weight 300N is lying rough

Engineering
1 answer:
kumpel [21]2 years ago
6 0

Answer:

Horizontal force = 89.2 N

Explanation:

The frictional force = coefficient of friction * magnitude of the force (weight of the body) * cos theta

Substituting the given values, we get -

Frictional Force = 0.3*300 * cos 25 = 89.2 N

Horizontal force = 89.2 N

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A cylindrical metal specimen of initial diameter d0 =14 mm, initial length L0=53 mm, strain hardening exponent n=0.31, strength
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a) Ef = 0.755

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d) Ft = 51874.67 N

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a) Determine the true strain at maximum load and true strain at fracture

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True strain at fracture

Ef = 0.755

b) determine the length of specimen at maximum load and diameter at fracture

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= 9.598 mm

c) Determine max load force

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d) Determine Load ( F ) on the specimen when a true strain et = 0.25 is applied during tension test

F = 51874.67 N

attached below is a detailed solution of the question above

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2 years ago
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