Answer:
2461.8 in²
Step-by-step explanation:
Area of a circle = r²π
Using r=28 and π=3.14:
Area = 28²×3.14 ≈ 2461.8 in² rounded to the nearest tenth (ans)
let's firstly convert the mixed fractions to improper fractions.
![\bf \stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}}~\hfill \stackrel{mixed}{1\frac{1}{3}}\implies \cfrac{1\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{4}{3}} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B7%7D%7B2%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%203%2B1%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf \begin{array}{ccll} miles&hours\\ \cline{1-2}\\ \frac{7}{2}&1\\[0.8em] m&\frac{4}{3} \end{array}\implies \cfrac{~~\frac{7}{2}~~}{m}=\cfrac{~~1~~}{\frac{4}{3}}\implies \cfrac{7}{2m}=\cfrac{3}{4}\implies 28=6m \\\\\\ \cfrac{28}{6}=m\implies \cfrac{14}{3}=m\implies 4\frac{2}{3}=m](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20miles%26hours%5C%5C%20%5Ccline%7B1-2%7D%5C%5C%20%5Cfrac%7B7%7D%7B2%7D%261%5C%5C%5B0.8em%5D%20m%26%5Cfrac%7B4%7D%7B3%7D%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B~~%5Cfrac%7B7%7D%7B2%7D~~%7D%7Bm%7D%3D%5Ccfrac%7B~~1~~%7D%7B%5Cfrac%7B4%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B7%7D%7B2m%7D%3D%5Ccfrac%7B3%7D%7B4%7D%5Cimplies%2028%3D6m%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B28%7D%7B6%7D%3Dm%5Cimplies%20%5Ccfrac%7B14%7D%7B3%7D%3Dm%5Cimplies%204%5Cfrac%7B2%7D%7B3%7D%3Dm)
Answer:
3/4→15/20 and 2/5→8/20
Step-by-step explanation:
4*5=20, do what you do to denominator to numerator, so 3*5=15. 15/20. Same for 2/5.
I believe your answer is 145
Answer:
A = 4 pi R^2 V = 4/3 pi R^3
A / V = 3 / R
Also, R = (3 * V / 4 * pi)^1/3 = (3 * 904.32 / (4 * pi))^1/3 = 6 in
So A = 3 / 6 * V = 1/2 * 904.32 = 452.16 in^2
