Does anyone have the answers to "INVERSES OF LINEAR FUNCTIONS COMMON CORE ALGEBRA II HOMEWORK"

Mathematics

1 answer:

Stells [14]3 years ago

3 0

Answer: hopefully this helps :)) download Socratic it helps a lot!!

Step-by-step explanation:

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Solve for W: P=2L + 2W A. W=P-L B. W= 1/2P - L C. W= 1/2 P + L D. W= 2P - L

svetlana [45]

Answer:

Step-by-step explanation:

$P=2L+2W$

$P-2L=2W$ (Subtract 2L from both sides of the equation)

$2W=P-2L$ (Symmetric Property of Equality)

$W=\frac{P-2L}{2}$ (Divide both sides of the equation by 2)

$W=\frac{P}{2} -\frac{2L}{2}$ ("Split" the fractions)

$W=\frac{1}{2}P-L$ (Simplify)

Hope this helps!

4 0

2 years ago

I desperately need this question answered. See attached image thanks so much

Dahasolnce [82]

For this case we must follow the steps below:

step 1:

We place each of the given points on a coordinate axis

Step 2:

We join the AC points (represented by the orange line)

We join the BD points (represented by the blue line)

It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.

In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: $m1 * m2 = -1$