Answer:
1 x 10^-4
Explanation:
Use the equation pH = -log[OH-}
Rearranging it [OH-] = 10^-pH
Plugging in we get [OH-] = 1 x 10^-4
Answer:
the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
The computation of the initial concentration of the SCN^- in the mixture is as follows:
As we know that

As it is mentioned in the question that KSCN is present 10 mL of 0.05 M
So, the total milimoles of SCN^- is
= 10 × 0.05
= 0.5 m moles
The total volume in mixture is
= 45 + 10 + 30
= 85 mL
Now the initial concentration of the SCN^- is
= 0.5 ÷ 85
= 0.00588 M
hence, the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
solid: table, biscuit
liquid: water, urine
gas: oxygen, carbon dioxide
According to Arrhenius theory of acid and base, Acids are those substances which when dissolved in water produces protons, while, Bases are those substances which when dissolved in water produces Hydroxyl Ions.
Example of Arrhenius Bases:
NaOH ₍s₎ → Na⁺ ₍aq₎ + ⁻OH ₍aq₎
LiOH ₍s₎ → Li⁺ ₍aq₎ + ⁻OH ₍aq₎
Result:
The only negative ion produced in water when Arrhenius Base is dissolved is ⁻OH (Hydroxyl Ion).