What is the molarity of a 2.0 L sodium hydroxide solution containing 10.0 grams of solute?
1 answer:
Molar mass NaOH ( sodium hydroxide) = 40.0 g/mol
Number of moles:
n = mass / molar mass
n = 10.0 / 40.0
n = 0.25 moles
Volume = 2.0 L
Molarity = number of moles / volume in liters
M = 0.25 / 2.0
M = 0.125 M
answer D
hope this helps!
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