Answer:
the second statement,the third&the fifth
I think it will be B. Hope it helps :)
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Data;
- Volume of solution = 260mL
- conc. of HCHO2 = 2.5*10^-2M
- conc. of NaCHO2 = 2.5*10^-2M
<h3>Mass of Reagent Added</h3>
To calculate the mass of reagent added, let's start with HCHO2
The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.

The mass of NaCHO2 to be added in the buffer solution is

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Learn more about buffer solution here;
brainly.com/question/22390063
The right answer for the question that is being asked and shown above is that: "B 1.5 X 1-^-5 ppm." A 250-mL aqueous solution contains 1.56 mc025-1.jpg 10–5 g of methanol and has a density of 1.03 g/mL. The concentration in ppm is that <span>1.5 X 1-^-5 ppm</span>
Answer:
Technician B is correct.
Explanation:
ASE exams are in 9 categories and they're based on real things that would happen in service shops in real life.