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Jet001 [13]
4 years ago
7

Marissa is learning about the unique properties of waves. She has learned that whenever the wavelength of a wave increases, the

frequency of the wave decreases. When does the speed of a wave change?
Group of answer choices

when a wave is reflected off a surface

when the wave encounters a new medium

when the amplitude of the wave changes

when the mass of the wave changes
Chemistry
1 answer:
Goshia [24]4 years ago
4 0

Answer:

I believe it is B

Explanation:

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Question 6(Multiple Choice Worth 2 points)
Rina8888 [55]
4.2 × 10²² atoms Al × (1 mol Al / 6.022 × 10²³) = moles Al

Last one: fraction 1 mole Al over 6.022 × 10²³ atoms Al
8 0
3 years ago
What is the nature of the Se-Cl bond in a molecule of selenium chloride (SeCl2) if the electronegativity value of selenium is 2.
ELEN [110]
MODERATELY POLAR COVALENT.
6 0
3 years ago
Read 2 more answers
Concerning the rate law, Rate = K[A]²[B], what are appropriate units for the rate<br> constant k?
vovikov84 [41]

The correct answer is M^-1s^-1.

The proportionality constant in the rate law expression, known as the rate constant or the particular rate constant, represents the relationship between the rate of the reaction and the concentration of the reacting species. Because it equals the rate of the reaction when the concentration of the reactants is assumed to be unity, it is known as the specific rate constant. The speed and direction of a chemical reaction are measured by a reaction rate constant. We are aware that the values of the Rate constant vary with temperature.

The given rate law is:

Rate = k[A][B]

The units of rate are always Ms^-1 and the units of [a] are mol so: mol*s^-1

Putting the units in the given rate law:

Rate = k[A][B]

Ms^-1=k×(M)×(M)

k=Ms^-1/M^2

k=M^-1s^-1

To learn more about  rate law refer the link:

brainly.com/question/14779101

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3 0
2 years ago
Distinguish between single and double replacement reactions and give an example of<br> each.
statuscvo [17]

Answer:

Anabolism builds complex molecules from simpler ones, while catabolism breaks large molecules into smaller ones.

Explanation:

5 0
3 years ago
The standard enthalpy of combustion of naphthalene is –5157 kj mol-1. calculate its standard enthalpy of formation. (use data in
Artemon [7]

The combustion of naphthalene is given as:

C10H8 (s) + 12 O2 (g) --> 10CO2 (g) + 4 H2O (l)

Enthalpy of combustion ΔH = -5157 kJ/mol

Now, the enthalpy change of a reaction is given

ΔH = ∑nΔHf (products) - ∑nΔHf (reactants)

where n = number of moles

            ΔHf = enthalpy of formation

Therefore,

ΔH = [10*ΔHf(CO2) + 4*ΔHf(H2O)] - [1*ΔHf(C10H8) + 12*O2]

-5157 = [10*(-393.5) + 4*(285.83)] - [ΔHf(C10H8) + 12*(0)]

ΔHf(C10H8) = 78.68 kJ/mol

4 0
4 years ago
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