D. y=x+2 is the correct answer because if you add two to the x values you get y.
15.4 seconds = 0.00428 hours and 100 meters = 0.062 miles soo the student ran approximately 14.5 mph
Answer:

Step-by-step explanation:
Remember the rule for converting radicals and exponents into fractions. The power is the numerator of the fraction, and the nth root is the denominator of the fraction. Also, remember that dividing by an exponent means the exponent will be negative.
![\frac{\sqrt[3]{x^{8} } }{\sqrt[6]{y^{5} } } \\\\\frac{x^{\frac{8}{3} } }{y^{\frac{5}{6} } } \\\\x^{\frac{8}{3}}y^{-\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%5E%7B8%7D%20%7D%20%7D%7B%5Csqrt%5B6%5D%7By%5E%7B5%7D%20%7D%20%7D%20%5C%5C%5C%5C%5Cfrac%7Bx%5E%7B%5Cfrac%7B8%7D%7B3%7D%20%7D%20%7D%7By%5E%7B%5Cfrac%7B5%7D%7B6%7D%20%7D%20%7D%20%5C%5C%5C%5Cx%5E%7B%5Cfrac%7B8%7D%7B3%7D%7Dy%5E%7B-%5Cfrac%7B5%7D%7B6%7D)
Answer:
Step-by-step explanation:
We have given that:
There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp. Each year, 10 new crocodiles join the swamp
Part A:
According to the above mentioned statement the function for representing the number of alligators and crocodiles in the swap throughout the year is:
Alligators = y=20(1.25)^x (x represents years)
crocodiles: y=10x+25
Part B:
Number of alligators after 4 years in the swap = y=20(1.25)^x
Number of alligators after 4 years in the swap = y=20(1.25)^4
Number of alligators after 4 years in the swap=48.82
This shows that about 48 to 49 alligators will be there in the swap after 4 year
Number of crocodiles after 4 years in the swap = y= 10(4)+25 = 65
Part C:
We will use the graph method to solve this part:
After approximately 7 years, the number of animals of each type will be the same, 95.
Their is no simplest form for your question because your answer would be <u>
46</u> 100.
Hope I helped you : )