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2 years ago

3 mm 4 mm What is the length of the hypotenuse? C = millimeters

Mathematics

2 answers:

valentina_108 [34]2 years ago

8 0

25 the length is 25 millimeters :)

Over [174]2 years ago

6 0

Answer:

25 is the answer

Step-by-step explanation:

25 is the answer

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Any chance anyone can help me if the last question I had post

german

Yes i can the answer would be question

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2 years ago

Lim<br> x->infinity (1+1/n)

FrozenT [24]

Answer:

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1$

Step-by-step explanation:

We want to evaluate the following limit.

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})$

We need to recall that, limit of a sum is the sum of the limit.

So we need to find each individual limit and add them up.

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}$

Recall that, as $n\rightarrow \infty,\frac{1}{n} \rightarrow 0$ and the limit of a constant, gives the same constant value.

This implies that,

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0$

This gives us,

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1$

The correct answer is D

5 0

3 years ago

Can you tell how many students got allowances of $15? Explain.

neonofarm [45]

5 because it says 11-16 which is one number before 15. dollars

5 0

2 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

How do I find out how many solutions does each system of equations have?

iragen [17]

To do that you should put it in slope intercept form and then graph, you should already know how to do this.

6 0

3 years ago

Read 2 more answers