Answer:
3520
Step-by-step explanation:
33-11=22
40 times 22=880
880 times 4=3520
<span> remainder is f(3) </span>
<span>3^3 - 6*3^2 - 9*3 + 3 </span>
<span>= 27 - 54 - 27 + 3 </span>
<span>= -51</span>
Hey there!
In order to solve this problem, you'll look at (x⁴)(3x³ – 2) first. You need to multiply 4x by both numbers in the binomial to get the distributed version that you'll use later on.
(x⁴)(3x³) = 3x⁷
(x⁴)(–2) = –2x⁴
Now, your problem is (3x⁷ – 2x⁴)(4x² <span>+ 5x). You will complete the distributing by multiplying the first term of the first binomial by both terms of the second binomial, then repeating this with the second term. You'll then want to add or subtract any repeated terms to combine them, if applicable. Remember that to multiply exponents together, all you need to do is add the numbers. x is the same as x</span>¹.<span>
</span>(3x⁷)(4x²) = 12x⁹
(3x⁷)(5x) = 15x⁸
(–2x⁴)(4x²) = –8x⁶
(–2x⁴)(5x) = –10x⁵
So, your final expanded product will be (12x⁹ + 15x⁸ – 8x⁶ – 10x⁵). Your answer should be letter A. Hope this helped you out! :-)
Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
Umm, since x is -3 (given), your answer should be B, since B is the only one with -3 as an x
hope this helps
