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Tatiana [17]
3 years ago
5

There is a 12 V potential difference between the positive and negative ends of the jumper cables, which are a short distance apa

rt. An electron at the negative end ready to jump to the positive and has a certain amount of potential energy. On what quantities does this electrical potential energy depend?
View Available Hintis) Hint 1. The expression for electric potential energy

a. only the distance between the ends of the cables
b. only the potential difference between the ends of the cables
c. only the charge on the electron
d. only the distance and the potential difference
e. only the distance and the charge
f. only the potential difference and the charge
g. the potential difference, charge, and distance
Physics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

Explanation:

The formula for the potential energy is given by

U = q x ΔV

where, U is the potential energy , q is the charge and ΔV is the potential difference.

So, the potential energy depends on the charge an the potential difference.

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Pls can anyone solve this​
gayaneshka [121]

Answer:

3 pls give me brainliest

Explanation:

8 0
3 years ago
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

6 0
3 years ago
Which statement describe a closed circuit ​
KiRa [710]
There are no statements shown?
4 0
3 years ago
A 1000 kg mass car moved in a straight, horizontal motion, with a speed of 20m / s, when it was involved in an accident. It was
emmasim [6.3K]

Answer:

average value of the resulting force

Explanation:

The average module value of this resulting force is equivalent to 2.0. 10⁵ N.

The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -

I = F.Δt

Where,

F = Strength in Newtons

Δt = time interval in seconds

I = Impulse in N.s

The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.

I = ΔQ

The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.  

Q = m-V

As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.

I = 0 - mV

F. Δt = - mV

F. 0,1 = - 1000. 20

F = - 20000/0,1

F = 200,000 N

F = 2,0. 10⁵ N

6 0
3 years ago
What is the average speed of a car that travels 60 meters in 2<br> seconds?
blondinia [14]

Answer:

30 m/s

Explanation:

Speed is distance over time. 60 meters / 2 seconds, = 30 m/s.

6 0
3 years ago
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