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ollegr [7]
3 years ago
15

What is power?

Physics
2 answers:
hammer [34]3 years ago
4 0
We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines are given in terms of Horsepower (hp) which is approximately equal to 745.7 watts.


Power is the rate at which a force is applied to an object for example.current wire
Snowcat [4.5K]3 years ago
4 0

Answer:

Power is the rate at which a force is applied to an objec

Explanation:

^-^

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When an object with a negative charge is moved from point A to point B through an external electrical field, it gains electrical
Sergio039 [100]

Explanation:

As per the problem,

           \Delta U = (V_{B} - V_{A})(-q) > 0

When q > 0 then -q is a negative charge . Since, change in potential energy (\Delta U) increases.

or,     (V_{A} - V_{B})q > 0

or,      V_{A} > V_{B}

Therefore, both positive and negative charge will move from V_{A} to V_{B} and as V_{B} < V_{A} so both of them move through a negative potential difference.

Thus, we can conclude that the true statements are as follows.

  • The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
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4 0
3 years ago
Just wondering if I did this right
Kisachek [45]

Yeah

All they are all correct

5 0
3 years ago
Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem
statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

x=x_o+v_1t    (1)

xo = 10 km

v1 = 55km/h

car 2:

x'=v_2t    (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}

t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s

The position in which both cars coincides is:

x=(55km/h)(0.33h)=18.33km

6 0
3 years ago
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