A 1000 kg mass car moved in a straight, horizontal motion, with a speed of 20m / s, when it was involved in an accident. It was
subjected for 0.1s to an intense force, coming to rest after that time interval, any time. is the mean value of the modulus of this resulting force?
1 answer:
Answer:
average value of the resulting force
Explanation:
The average module value of this resulting force is equivalent to 2.0. 10⁵ N.
The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -
I = F.Δt
Where,
F = Strength in Newtons
Δt = time interval in seconds
I = Impulse in N.s
The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.
I = ΔQ
The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.
Q = m-V
As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.
I = 0 - mV
F. Δt = - mV
F. 0,1 = - 1000. 20
F = - 20000/0,1
F = 200,000 N
F = 2,0. 10⁵ N
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Answer:
Amount of linear movement
Explanation:
Our system is defined by the rate of change in mass that
leaves the car , this happens during a time interval
, in addition to freight car and sand at time t.
In this way we need to define the two states:
State 1,
consider and V.
State 2,
consider
In this state is the mass of sand output, which
is composed of
In this way we define the Linear movement in x, like this:
In this way we proceed to obtain the Force
Since the mass of the second term becomes 0, the same term is eliminated, thus,
Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
=
= 10 m/s
<span><u>Note that this one is the final velocity.</u></span><u />
We also know that,
initial velocity (u) = 0 m/s .......<span> because the car starts from rest.
</span>Now,
=
=
= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....<span>note that displacement is same as distance.
</span><span> = 1200 N * 100 m
</span> = 120000 N.m
= 120000 J
Now,
Power (P) =
=
= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
=
= 10 m/s
<span><u>Note that this one is the final velocity.</u></span><u />
We also know that,
initial velocity (u) = 0 m/s .......<span> because the car starts from rest.
</span>Now,
=
=
= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....<span>note that displacement is same as distance.
</span><span> = 1200 N * 100 m
</span> = 120000 N.m
= 120000 J
Now,
Power (P) =
=
= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.