p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Step-by-step explanation:
Pete has already completed 27 missions. Pete plans to complete 3 missions per week
Let x represents weeks
Games completed = 3x + 27
Sophie has only completed 13 missions. Sophie plans to complete 5 missions per week.
Games completed = 5x + 13
3x + 27 = 5x + 13
27 - 13 = 5x - 3x
2x = 14
x = 7
By the seventh week, they would have completed equal number of games,
There is no sum for this geometric series. it diverges rather than converges due to the absolute value of the common ratio (r), which is -3, being 3. for a geometric series to have a sum (to converge), the absolute value of r must be less than 1.
(you find r by dividing a2/a1, a3/a2, etc.)
hope this helps
Answer:
£153
Step-by-step explanation:
If Saji bought a normal ticket for all 19 games, they would have to make 19 payments of £28. So, 28*19 would let us know that he would spend £532 in total. Then it's simply 532-379 to find the answer.
A+b+c=408
a=a
b=7+a
c=5+a
a+(7+a)+(5+a)=408
3a+12=408
3a=396
a=132
Abel has $132
Belle has $139
Cindy has $137
Prove:
132+139+137=408
