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slavikrds [6]
3 years ago
5

I need help... on my homework it says to write each expression in radical form, or write each radical and exponential form . For

one of the problems it is:
√13 How would I solve this?
Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{13}\implies \sqrt[2]{13^1}\implies 13^{\frac{1}{2}}

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Help pls thank you!!!!
Semmy [17]

Answer:

y = 16

Step-by-step explanation:

You would plug in the value given for x into the function given.

\frac{1}{3}(18) + 10

Type that into a calculator and this would give you the output, which would be the value for Y.

The value for Y is 16.

Hope this helps.

8 0
2 years ago
Read 2 more answers
What is the term for the likelihood that a correlation exists in a population, based on knowledge of the actual value of r in a
zvonat [6]

Answer:

Statistical significance

Step-by-step explanation:

The Statistical significance provides a link between the  dependent and the independent variable. It provides us the indication that the change in the independent variable is correleated with the shift caused in the dependent variable.

6 0
3 years ago
LITTERLY HELP ME PLEASEE..... 2/x-4x/2x-3=-2<br> PLEASEE I INSERTED A PIC
Stels [109]

Answer:

x = -3

Step-by-step explanation:

Given expression is,

\frac{2}{x}- \frac{4x}{2x-3}=-2

\frac{2(2x-3)}{x(2x-3)}-\frac{4x(x)}{x(2x-3)}=-2

\frac{2(2x-3)-4x^{2} }{x(2x-3)}=-2

(4x - 6) - 4x² = -2x(2x - 3)

4x - 6 - 4x² = -4x² + 6x

4x - 6 = 6x

6x - 4x = -6

2x = -6

x = -3

3 0
3 years ago
If AP 10 - 12. what is the perimeter of quadrilateral TAEO (a) 56 (b)64 (c)72 (d)76​
BlackZzzverrR [31]

Husofjwiebd9ks ueijddlonf durnkofbjus yuebejuiiiiiiiiijjd dijdjdjdnsjduwjwuwhw

4 0
3 years ago
A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form
Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity v_o of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

h = -16t^2 +v_ot + 8

Thus;

Replacing the value of v_o =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

0= -16t^2 +(1120)t + 8

=  -16t^2 +(1120)t + (8-0)

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}, we have:

= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}

= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}

= \dfrac{140 \pm \sqrt{19608}}{4}

= \dfrac{140 \pm 140}{4}

=\dfrac{140+ 140}{4} \ \ \ OR \ \ \  \dfrac{140-140}{4}

=\dfrac{280}{4} \ \ \ OR \ \ \  0

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

6 0
2 years ago
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