Answer:
The usually speed of the bus is 50 miles/h.
Step-by-step explanation:
Let the usual speed of the bus be x mile/hour.
We know that
The bus travels 200 miles.
To reach its destination it takes time 
h
This week however the bus leaves at 5:40.
The bus late 40 minutes 
Now the speed of the bus is = (x+10) miles/h
The new time to reach the destination is 
h
According to the problem,
![\Rightarrow 200[\frac{x+10-x}{x(x+10)}]=\frac{2}{3}](https://tex.z-dn.net/?f=%5CRightarrow%20200%5B%5Cfrac%7Bx%2B10-x%7D%7Bx%28x%2B10%29%7D%5D%3D%5Cfrac%7B2%7D%7B3%7D)
![\Rightarrow 200[\frac{10}{x^2+10x}]=\frac{2}{3}](https://tex.z-dn.net/?f=%5CRightarrow%20200%5B%5Cfrac%7B10%7D%7Bx%5E2%2B10x%7D%5D%3D%5Cfrac%7B2%7D%7B3%7D)
⇒2(x²+10x)=200×10×3
⇒x²+10x = 3000
⇒x²+10x -3000=0
⇒x²+60x-50x-3000=0
⇒x(x+60)-50(x+60)=0
⇒(x+60)(x-50)=0
⇒x= -60,50
∴x=50 [since speed does not negative]
The usually speed of the bus is 50 miles/h.
The required two-digit number is 75.
<h3>What is arithmetic?</h3>
In mathematics, it deals with numbers of operations according to the statements.
let the number in tenth place be x.
And has two fewer units than tens.
= x - 2
The two-digit number can be given as
= 10x + (x - 2)
= (11x - 2)
Reversing the digits
= (x - 2)10 + x
= 11x -20
The difference between twice the number and the number reversed is 93.
Now the required two-digit number is,
= 11x -2
= 11*7 - 2
= 77 -2
= 75
Thus the required two-digit number is 75.
Learn more about arithmetic here:
brainly.com/question/14753192
#SPJ1
2.00/6 = $0.33 rounded to the nearest penny, it actually is $0.333333333333 (infinite)
I hope this helped you out :)
Add 10 + 10 + 6 + 6 = 32
32 ft.
I dont know if you wanted the steps but:
x^2-4x-6=0
plug it into the equation:
![[tex] \frac{4\sqrt{40}}{2}](https://tex.z-dn.net/?f=%20%5Btex%5D%20%5Cfrac%7B4%5Csqrt%7B40%7D%7D%7B2%7D%20)
[/tex]
x^2-4/3x+1/3 x=1 , x= 1/3
2x^2-3x+1=0 x=1 , x=1/2
6x^2+12x=-5
add the 5 to both sides
6x²+12x+5=0 plug the problem into the equation
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