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3 years ago

Which of the following actions is NOT

Physics

2 answers:

Eduardwww [97]3 years ago

3 0

Answer:

Explanation: because it wont effect the animals home

Tasya [4]3 years ago

3 0

Answer: D because camping is not

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A playground merry-go-round of radius r = 2.00 m has a moment of inertia = 250 ⋅ , and is rotating at 10.0 rev/min about a frict

bagirrra123 [75]

Answer:

$330kgm^2$

Explanation:

We are given that

Radius,r=2 m

Moment of inertia,I=250 $kgm^2$

Angular velocity, $\omega_1=10 rev/min$

Mass of child,m=20 kg

We have to find the new moment of inertia of the merry go round.

New moment of inertia , $I'=mr^2+I$

Using the formula

$I'=20(2)^2+250$

$I'=80+250=330kgm^2$

Hence, the new moment of inertia of the merry -go-round= $330kgm^2$

8 0

3 years ago

A disk between vertebrae in the spine is subjected to a shearing force of 425 N. Find its shear deformation, taking it to have a

zzz [600]

Answer:

option A

Explanation:

given,

shear force = 425 N

Shear modulus = 1.7 × 10⁹ N/m²

disk equivalent to solid cylinder

height = 0.7 cm and diameter = 6.50 cm

$\delta = \dfrac{VL}{AG}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi d^2\times 1.7\times 10^9}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi\times 0.065^2\times 1.7\times 10^9}\\\\\delta = 5.27 \times 10^{-7} m$

hence, the correct answer is option A

3 0

4 years ago

PLzzz helpppp

ioda

Answer: Charging.

Explanation: ...

5 0

2 years ago

Read 2 more answers

A wire with a linear mass density of 1.19 g/cm moves at a constant speed on a horizontal surface and the coefficient of kinetic

scZoUnD [109]

Answer:

The magnitude and direction of the smallest magnetic field that can accomplish this are 0.172 T and vertically to the east.

Explanation:

given information:

density of wire, m/l = 1.19 g/cm = 0.119 kg/m

coefficient of kinetic friction, μk = 0.250

current, I = 1.7 A

according to the Newton's first law

∑F = 0

F(magnetic) - F(friction) = 0

F(magnetic) = F(friction)

F(magnetic) = B i l sin θ

where

F (magnetic) = magnetic force

B = magnetic field (T)

i = current (A)

l = the length of wire (m)

θ = angle

and

F(friction) = μk N

where

F(friction) = kinetic force (N)

μk = coefficient of kinetic friction

N = Normal force (N)

so,

F(magnetic) = F(friction)

B i l sin θ = μk N

B = μk N/i l sin θ

now lets determine the normal force

N - mg = 0

N = mg

therefore

B = μk mg/i l sin θ

θ = 90° because the magnetic field is perpendicular to the wire (smallest magnetic field)

B = μk mg/i l sin 90

= μk mg/i l

= (μk g/i) (m/l)

= ((0.250) (9.8) / (1.7)) ((0.119)

= 0.172 T

according to the right hand rule, the direction of the magnetic field is vertically to the east. (magnetic force to the south and current to the westward)

8 0

3 years ago

A large reflecting telescope has an objective mirror with a 14.0 m radius of curvature. What angular magnification in multiples

goldenfox [79]

Answer:

The magnification is $m = -2.15$