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Oksanka [162]
2 years ago
13

In a given chemical reaction, the energy of the products is less than the energy of the reactants. Which statements is true for

this chemical reaction
Physics
2 answers:
ArbitrLikvidat [17]2 years ago
8 0

B: Energy Is Released In The Reaction.

Inessa05 [86]2 years ago
7 0

Answer:It is an Endothermic reaction

Explanation:

Exothermic reaction

An exothermic reaction is one that releases energy in the form of heat or light.

Endothermic reaction

An endothermic reaction is one that absorbs energy in the form of heat or light.

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In the equation for centripetal force, which expression represents the centripetal acceleration of the object? mv2 StartFraction
Sphinxa [80]

Answer: \frac{V^{2}}{r}

Explanation:

According to Newton's 2nd Law of motion the force F is proportional to the mass Fm and acceleration a:

F=m.a (1)

On the other hand, the equation for the Centripetal force is:

F=\frac{mV^{2}}{r} (2)

Where:

V is the velocity

r is the radius of the circular motion

Making (1) and (2) equal:

m.a=\frac{mV^{2}}{r} (3)

Hence:

a=\frac{V^{2}}{r} This is the expression for the centripetal acceleration

It should be noted, this acceleration is directed toward the center of the circumference of the circular motion (that's why it's called centripetal acceleration).

3 0
3 years ago
Read 2 more answers
What force, in newtons, must you exert on the balloon with your hands to create a gauge pressure of 62.5 cm H2O, if you squeeze
yulyashka [42]

Answer:54.70 N

Explanation:

Given

Gauge Pressure of 62.5 cm of H_2O

i.e. h=62.5 cm =0.625 m

Effective area A=51 cm^2

initial Pressure= 1 atm=101.325 kPa

Gauge Pressure P=\rho gh

\rho =density\ of\ water =1000 kg/m^3

P_{gauge}=1000\times 9.8\times 0.625=5.937 kPa

Force creates a pressure of P_1 which will be equal to Gauge Pressure

P_1=\frac{F}{A}

P_1=P_{gauge}

\frac{F}{A}=5.937 kPa

F=5.937\times 51\times 10^{-4}\times 10^3

F=30.27 N

6 0
3 years ago
Guillaume puts a bottle of soft drink in a refrigerator and leaves it there until its temperature has dropped 15.1 K.
Zarrin [17]

Answer: (a) The magnitude of its temperature change in degrees Celsius is 15.1^{o}C.

(b) The magnitude of the temperature change (change in T = 15.1 K) in degrees Fahrenheit is 27.2^{o}F.

Explanation:

(a)  Expression for change in temperature is as follows.

        |\Delta T| = |x - y|K

                         = 15.1 K

                    = |(x - 273.15) - (y - 273.15)|^{o}C

                    = |x - y|^{o}C

                    = 15.1^{o}C

Therefore, the magnitude of its temperature change in degrees Celsius is 15.1^{o}C.

(b)  Change in temperature from Celsius to Fahrenheit is as follows.

           F = 1.8C + 32

          C = \frac{F - 32}{1.8}

Since,   K = C + 273

or,    \Delta K = \Delta C = \frac{\Delta F}{1.8}

         \Delta F = 1.8 \Delta K

                      = 1.8 (15.1)

                      = 27.18^{o}F

or,                  = 27.2^{o}F

Thus, we can conclude that the magnitude of the temperature change (change in T = 15.1 K) in degrees Fahrenheit is 27.2^{o}F.

7 0
2 years ago
Read 2 more answers
This same car gets pulled over for speeding, and goes from 68 m/s to 0 m/s in 14
Harrizon [31]

Answer:

the acceleration of the car is -4.9m/s2.

the direction is opposite to the actual direction, since the acceleration is negative.

3 0
2 years ago
Water has the ability to dissolve polar covalent molecules like sucrose by
Alla [95]

Explanation:

Sucrose is a disaccharide which is composed of fructose and glucose. Sucrose molecule has oxygen atoms bonded to hydrogen atoms (O-H bonds - Polar groups) on all ends of its double 6-Carbon ring. The areas near the oxygen atoms are slightly negative, and the areas near the hydrogen atoms are slightly positive that is, the O-H bonds are polar. They bond with the neighbouring Oxygen and Hydrogen atoms because of their

dipole - dipole attractions and hence hydrogen bonds are formed.

However, the covalent bonds within the molecule aren't broken. But rather, the hydrogen bonds holding the sucrose molecules in the crystalline lattice.

5 0
2 years ago
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