Question

A large reflecting telescope has an objective mirror with a 14.0 m radius of curvature. What angular magnification in multiples does it produce when a 3.25 m focal length eyepiece is used? ✕

Answer 1

Answer:

The magnification is  $m = -2.15$

Explanation:

From the question we are told that

   The  radius is  $r = 14.0 \ m$

    The  focal length eyepiece is  $f_e = 3.25 \ m$

Generally the objective focal length is mathematically represented as

        $f_o = \frac{r}{2}$

=>     $f_o = \frac{14}{2}$

=>     $f_o = 7 \ m$

The  magnification is mathematically represented as

      $m = - \frac{f_o }{f_e }$

=>    $m = - \frac{7 }{ 3.25 }$

=>   $m = -2.15$