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4 years ago

6

A large reflecting telescope has an objective mirror with a 14.0 m radius of curvature. What angular magnification in multiples

does it produce when a 3.25 m focal length eyepiece is used? ✕

1 answer:

goldenfox [79]4 years ago

5 0

Answer:

The magnification is $m = -2.15$

Explanation:

From the question we are told that

The radius is $r = 14.0 \ m$

The focal length eyepiece is $f_e = 3.25 \ m$

Generally the objective focal length is mathematically represented as

$f_o = \frac{r}{2}$

=> $f_o = \frac{14}{2}$

=> $f_o = 7 \ m$

The magnification is mathematically represented as

$m = - \frac{f_o }{f_e }$

=> $m = - \frac{7 }{ 3.25 }$

=> $m = -2.15$

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