Answer:
To find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and <u>Emissivity of the Filament</u>.
Explanation:
The emissive power of a light bulb can be given by the following formula:
E = σεAT⁴
where,
E = Power Input or Emissive Power
σ = Stefan-Boltzmann constant
ε = Emissivity
A = Area
T = Absolute Temperature
Therefore,
A = E/σεT⁴
So, to find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and <u>Emissivity of the Filament</u>.
Answer:
the angle is given by
Tan theta = 35/59 = 0.59
so theta = Tan ^-1 ( 0.59 )
theta = 30.54 deg.
Answer:
C. Takes heat in, does work, and loses energy heat.
Explanation:
Heat engine is a system makes use of thermal energy (heat) to in order to do mechanical work.
This occurs by converting the heat into mechanical energy. This energy is then used to do work.
The key characteristic of a heat engine is that the substance with which work is done by, goes from a higher temperature to a lower temperature.
Hence, it loses heat as it does work.
Answer:
176 min
Explanation:
456 g = .456 kg
Specific heat of ice s = 2093 J kg⁻¹
Heat required to raise the temperature by 25 degree
= mass x specific heat x rise in temperature.
= .456 x 2093 x 25
=23860 J
Heat required to melt the ice to make water at zero degree
= mass x latent heat
= .456 x 334 x 10³
=152304 J
Total heat required = 152304 + 23860 = 176164 J .
Time Required = Heat required / rate of supply of heat
= 176164 / 1000
176.16 min
