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4 years ago

3. Use the benchmark percents to determine each value

Mathematics

1 answer:

zlopas [31]4 years ago

7 0

Answer:

a = 300

b = 150

c = 60

d = 30

e = 6

To find the answer:

One way is to put the percents into fractions simplest form and divide by 600.

So:

a = 1/2

b= 1/4

c = 1/10

d = 1/20

e = 1/100

Divide these by 600, you get the same answers.

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The Advanced Way:

To find a percent, you (can) turn the percents into fractions and multiply the number from the fraction.

For example: Question A:

600 x 1/2 = 300

You get the same answers as the ordinary version too. From right above Advanced.

Have a great evening, good luck on your homework.

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HELP PLEASE

OLEGan [10]

Answer:

Point E on the number line represents the approximate volume of a cylinder with a radius of 4 units and height of 4 units.

Step-by-step explanation:

It is given that the radius of the cylinder is 4 units and the height of the cylinder is 4 units.

The volume of the cylinder is

$V=\pi r^2h$

Where, r is radius and h is height of the cylinder.

Substitute r=4, h=4, π=3.14 in the above formula.

$V=(3.14)\times (4)^2\times (4)$

$V=200.96$

The volume of the cylinder is 200.96. Therefore, point E on the number line represents the approximate volume of a cylinder with a radius of 4 units and height of 4 units.

3 0

4 years ago

Pls answer! I don’t know math @ all

Lana71 [14]

The probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is $\frac{5}{12}$ .

Solution:

Total number of outcomes N(S) = 36

Let A be the sum that is a multiple of 6 and

B be the sum that is a multiple of 4.

Sum that is a multiple of 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (6, 6)

N(A) = 6

Sum that is a multiple of 4 = (1, 3), (2, 2), (2, 6), (3, 1), (3, 5),

(4, 4), (5, 3), (6, 2), (6, 6)

N(B) = 9

$$P(A)=\frac{N(A)}{N(S)}$

$$P(A)=\frac{6}{36}=\frac{1}{6}$

$$P(B)=\frac{N(B)}{N(S)}$

$$P(B)=\frac{9}{36}=\frac{1}{4}$

Probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4:

$P(A \cup B)=P(A)+P(B)$

$$P(A \cup B)=\frac{1}{6} +\frac{1}{4}$

$$=\frac{2+3}{12}$ (Make the denominator same)

$$=\frac{5}{12}$

Hence the probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is $\frac{5}{12}$ .

8 0

3 years ago

emma lee is shopping for supplies for her science project. The regular price of the supplies at a hardware store is $20. The sto

zmey [24]

Answer:

First, you add 30 and 20, and you get 50. Then, since 30 is your highest priced item, you find 0.30 of 30, which is 9. After that you would subtract 9 from 30, which gives you 21. Therefore, we know the price is 41

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Can someone solve and explain how to do this for me

Jobisdone [24]

Ok
You look at how many ‘x’ there are then you add them together 6x+3x+x+10+40=180
I think you can take it from here?

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4 years ago

Part B) Which of the following functions most appropriately models the data, where

Olegator [25]

Answer:

its c

Step-by-step explanation:

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4 years ago