Answer:
How many positive integers under 50 are multiples of neither 4 nor 6
1 answer:
Candidates range from 1 to 50.
50/4=12 positive integers are multiples of 4
50/6=8 positive integers are multiples of 6
50/12=4 positive integers are multiples of 12 (LCM of 4 and 6)
By the inclusion/exclusion principle, the number of multiples of either 4 or 6 is equal to 12+8-4=16.
Therefore, the complement is the number of positive integers that are multiples of neither 4 nor 6 = 50-16=34.
50/4=12 positive integers are multiples of 4
50/6=8 positive integers are multiples of 6
50/12=4 positive integers are multiples of 12 (LCM of 4 and 6)
By the inclusion/exclusion principle, the number of multiples of either 4 or 6 is equal to 12+8-4=16.
Therefore, the complement is the number of positive integers that are multiples of neither 4 nor 6 = 50-16=34.
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Answer: You start to ascend
Explanation:
Since you are walking due south and the positive y-axis points north, the y-coordinate decreases.
Let
= y-coordinate after walking due south
= z-coordinate (or the height) after walking due south
So, the point where you stand after walking due south has a coordinate of
. Moreover,
Since the y-coordinate decreases after walking due south and
,
So, the height after walking due south exceeds 1,206 meters, which is the previous height before walking due south. Therefore, if you walk due south from point with coordinates (100, 120, 1206), you are ascending.
Explanation:
Since you are walking due south and the positive y-axis points north, the y-coordinate decreases.
Let
So, the point where you stand after walking due south has a coordinate of
Since the y-coordinate decreases after walking due south and
So, the height after walking due south exceeds 1,206 meters, which is the previous height before walking due south. Therefore, if you walk due south from point with coordinates (100, 120, 1206), you are ascending.
The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
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