You have to check which of the following expressions is the rational exponent expression of third root of 4n, or mathematically, ![\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B4n%7D%20.%20)
Consider all cases:
A. ![(4n)^3=4^3\cdot n^3=64n^3\neq\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%284n%29%5E3%3D4%5E3%5Ccdot%20n%5E3%3D64n%5E3%5Cneq%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
B. ![3n^4\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%203n%5E4%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
C. quantity of 4n to the one third power is ![(4n)^{\frac{1}{3} }=\sqrt[3]{4n}](https://tex.z-dn.net/?f=%20%284n%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D%5Csqrt%5B3%5D%7B4n%7D%20)
(by the definition of rational power).
D. 4 times n to the one third power is ![4\cdot n^{\frac{1}{3} }=4\sqrt[3]{n}\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%204%5Ccdot%20n%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D4%5Csqrt%5B3%5D%7Bn%7D%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
Answer: correct choice is C.
Answer:
<h3>y*5-8=47</h3><h3>y*5=47+8</h3><h3>y*5=55</h3><h3>y=55/5</h3><h3>y=11</h3>
For this case, the first thing we must do is apply the law of the sine.
We then have the following expression:
sine (65) / x = sine (104) / 36
Clearing the value of x we have:
x = (sine (65) / sine (104)) * (36)
x = 33.6 feet
Answer:
The distance between the sandbox and garden is:
x = 33.6 feet
7) Skateboarding down a hill or a ramp. Rolling a ball on the floor. Going up and down the ramp of a moving truck.
8) Throwing a ball into the air and then catching it. Skateboarding a half-pipe. Shooting a basketball. Hitting a baseball.
Answer: it seems to be D, but the equation makes practically no sense!
The value of the factor changes for the different amounts of service years and vacation weeks.
Step-by-step explanation: The equation means that the employee is trying to figure out the value of the "v-factor" for how vacation time is earned.
If you substitute the number of service years into the left side of the "formula" and vacation weeks on the right side, then solve for "v", v(15)=5 you get v= 1/3 or 0.33
If you substitute other numbers, like v(2)=2, so v= 1 then v(30) = 8, v = 4/15 or 0.2667. You see the factor's value decreases. The company is much more generous to to employees with one or two years of service than with the older ones.
