Question

a scientist is measuring the measuring the temperature change in a chemical compound. the temperature dropped 11 per hr from the original temperature after 4 hrs the temperature was 90 find the compounds. original temperature​

Answer 1

Answer:

$\large \boxed{134 \, ^{\circ}\text{C}}$

Explanation:

1. Calculate the temperature drop

$\text{Temperature drop} = \text{4 h} \times \dfrac{11 \,^{\circ}\text{C}}{\text{1 h}} = 44 \,^{\circ}\text{C}$

2. Calculate the original temperature

$\begin{array}{rcl}\text{Final Temperature} & = & \text{original temperature - temperature drop}\\90 ^{\circ}\text{C} & = & \text{original temperature - 44} \, ^{\circ}\text{C}\\\text{Original temperature}& = & \mathbf{134 \, ^{\circ}}\textbf{C}\\\end{array}\\\text{The original temperature was \large \boxed{\mathbf{134 \, ^{\circ}}\textbf{C}} }$