Answer:
77 L of water can be made.
Explanation:
Molar mass of 
= 32 g/mol
So, 55 g of = 
mol of = 1.72 mol of
As hydrogen is present in excess amount therefore is the limiting reagent.
According to balanced equation, 1 mol of produces 2 mol of 
.
So, 1.72 mol of produce 
mol of or 3.44 mol of .
Let's assume gas behaves ideally at STP.
Then, 
, where P, V, n, R and T represents pressure, volume, no. of moles, gas constant and temperature in kelvin scale respectively.
At STP, pressure is 1 atm and T is 273 K.
Here, 
= 3.44 mol and R = 0.0821 L.atm/(mol.K)
So, 
Option (b) is correct.
Answer:
CO2
Explanation:
(I Just took the test)
At STP 1 mol=22.4 Liters, so we now know that it is asking for which of the gasses has a molar mass of 44, and CO2 is th only one with that molar mass
The cis and Trans-forms of hyponitrous acid are given below in the attached document.
Hyponitrous acid has the chemical formula H2N2O2 or HON=NOH. 62.028 g/mol is the molecular weight of it. Additionally, it can take either a trans or cis form. When dry, the trans-hyponitrous acid crystallizes into white, explosive particles. Additionally, it has a half-life of 16 days at 25oC at a pH 1-3 in aqueous solution and is a weak acid (pKa1=7.21, pKa2=11.54). It decomposes into nitrous oxide and water. It is incorrect to think of N2O as the anhydride of H2N2O2. However, even though cis acid is unknown, we can still get its sodium salts.
Learn more about explosive particles here-
brainly.com/question/21437871
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Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
