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3 years ago

After your product alkyl ether is recrystallized and dried how do you test the purity

Chemistry

1 answer:

VLD [36.1K]3 years ago

3 0

Answer: Use of Etherificarion followed by fractional distinction.

Explanation:

It is done by reacting a mixture of tetrahydrofurfuryl alcohol and up to about one equivalent of at least one low work function element, Reacting the said mixture with a halide; fractionally distilling said reacted mixture to yield the first distillate; reacting said first distillate with an excess amount of at least one low work function element; and, fractionally distilling said reacted first distillate to obtain the purified ether wherein said at least one low work function element is an elemental metal or a metal hydride which has a φ of less than about 3.0 eV.

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Differentiate between ideal and non - ideal solutions. <img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title

nordsb [41]

Answer:

Ideal Solution: An ideal solution is a solution where interactions between molecules are identical between all the molecules in the solution. Non ideal Solution: A non ideal solution is a solution that has differences in the interactions between molecules of different components in the solution.

Explanation:

3 0

2 years ago

Read 2 more answers

A sample of 9.27 g9.27 g of solid calcium hydroxide is added to 38.5 mL38.5 mL of 0.500 M0.500 M aqueous hydrochloric acid. Writ

navik [9.2K]

Answer: The excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For calcium hydroxide:

Given mass of calcium hydroxide = 9.27 g

Molar mass of calcium hydroxide = 74.093 g/mol

Putting values in above equation, we get:

$\text{Moles of calcium hydroxide}=\frac{9.27g}{74.093g/mol}=0.125mol$

To calculate the moles of a solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Volume of hydrochloric acid = 38.5mL = 0.0385 L (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.500 moles/ L

Putting values in above equation, we get:

$0.500mol/L=\frac{\text{Moles of hydrochloric acid}}{0.0385L}\\\\\text{Moles of hydrochloric acid}=0.01925mol$

For the given chemical equation:

$2HCl(aq.)+Ca(OH)_2(s)\rightarrow CaCl_2(s)+2H_2O(l)$

Here, the solid salt is calcium chloride.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium hydroxide.

So, 0.01925 moles of hydrochloric acid will react with = $\frac{1}{2}\times 0.01925=0.009625moles$ of calcium hydroxide.

As, given amount of calcium hydroxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (calcium hydroxide) left = 0.125 - 0.01925 = 0.115375 moles

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.01925 moles of hydrochloric acid will produce = $\frac{1}{2}\times 0.01925=0.009625moles$ of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 110.98 g/mol

Moles of calcium chloride = 0.009625 moles

Putting values in equation 1, we get:

$0.009625mol=\frac{\text{Mass of calcium chloride}}{110.98g/mol}\\\\\text{Mass of calcium chloride}=1.068g$

Hence, the excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

5 0

3 years ago

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EASY PLEASE HELP !!!!!!

Fantom [35]

Answer: B.) Salt and water

Explanation: A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.

Hope this helps :)

7 0

3 years ago

Read 2 more answers

Determine the value of x and write the complete chemical formula of the hydrate

Annette [7]

In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation 2.12.

7 0

3 years ago

1 It was found that 4n atoms of metal x

raketka [301]

Answer:

C 108

Explanation:

1 It was found that 4n atoms of metal x

weigh 501.6 g. The relative atomic mass

of X is 209. If n atoms of another metal,

Y, weigh 65.00 g, what is the relative

atomic mass of metal Y?

A 27 B 52 C 108 D 137

if 4n atoms of x weigh 501.6 gm, the n atoms weigh 501.6/4 = 125.4 gms

since the atomic mass is 209, then 6.022 X10^23 atom weigh 209

the ratio of 125.4 to 209 is

125.4/Y =0.6

therefor n is the number of atom in 0.6 moles

if metal Y has the same, number of atoms "n" and weighs 65 gm

then then the relative atomic mass is

65/0.6 =108

so the answer is

C 108

7 0

3 years ago