Identify the oxidation numbers for all the elements in the reactants and products for 4H2O2(aq)+Cl2O7(g)+2OH−(aq)→2ClO2−(aq)+5H2

Question

4 years ago

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Identify the oxidation numbers for all the elements in the reactants and products for 4H2O2(aq)+Cl2O7(g)+2OH−(aq)→2ClO2−(aq)+5H2

O(l)+4O2(g) Identify the oxidation numbers by dragging the appropriate labels to their respective targets. ResetHelp -7-7 -5-5 -4-4 -3-3 -2-2 -1-1 00 +1+1 +2+2 +3+3 +4+4 +5+5 +7+7

Chemistry

1 answer:

Nadusha1986 [10] · Answer 1 · 2021-12-13T16:36:22+03:00

Answer:

H₂O₂: H (+1); O (-1)

Cl₂O₇: Cl (+7); O (-2)

OH⁻: O (-2); H (+1)

ClO₂⁻: Cl (+3); O (-2)

H₂O: H (+1); O (-2)

O₂: O (0)

Explanation:

The oxidation number (o.n.) is the number of electrons an atom tends to gain or lose to form a chemical bond and gain stability.

In H₂O₂, H has the o. n. +1 (its most common o. n.) and O has the o.n. -1 in the peroxide ion O₂²⁻.
In Cl₂O₇, Cl has the o.n. +7 (its highest o.n.) and O has the o.n. -2 (its most common o.n.)
In OH⁻, O has the o.n -2 and H has the o.n. +1.
In ClO₂⁻, Cl has the o.n. +3, and O has the o.n. -2. Cl has undergone a reduction.
In H₂O, O has the o.n -2 and H has the o.n. +1.
By definition, in O₂, O has the o.n. 0. It has undergone oxidation.