Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ = ![\frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5E2%5BS_%7B2%7D%5D%7D%7B%5BH_%7B2%7DS%5D%5E2%7D)
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:
We make a simplification because x<<< 0.0225:
x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M
An Ionic bond is when you have a metal and a nonmetal element bonded together. In this kind of bonds, the metal atom takes electrons from the nonmetal. on other words, this bond involves the gaining and losing of electrons. The atom that receives the electrons becomes an anion (negatively charged ion) and the one that loses them becomes the cation (positively charged ion)
A covalent bond is a bond created between two nonmetals element. In here, both atoms share the electrons.
Both bonds involve interaction between atoms.
Answer:
Fe2O3 + C → 2Fe + CO3
Explanation:
The unbalanced equation given in this question is as follows:
Fe2O3 + C → Fe + C03
To balance this equation, one should ensure that the number of atoms of each element on both sides of the equation is equal. The balanced equation is as follows;
Fe2O3 + C → 2Fe + CO3
N.B, there are;
- 2atoms of Fe on both sides
- 1 atom of C on both sides
- 3 moles of O on both sides
Answer:
Total pressure = 1109.2 torr
Explanation:
Given data:
Partial pressure of cyclopropane = 334 mmHg
Partial pressure pressure of oxygen = 1.02 atm
Total pressure of mixture = ?
Solution:
Formula:
Total pressure = P of C₃H₆ + P of O₂
1 atm = 760 torr = 760 mmHg
1.02 atm × 760 torr / 1atm = 775.2 torr
Total pressure = P of C₃H₆ + P of O₂
Total pressure = 334 torr + 775.2 torr
Total pressure = 1109.2 torr
