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FromTheMoon [43]
3 years ago
15

roger completed a probability experiment with a coin. he flipped the coin 32 times, and it landed on tails eight times. he looke

d at the results of his experiment to determine the ratio of heads outcomes to tails outcomes.
Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0
I don't know what this question is asking exactly, but if i am right, it is asking for the ratio of heads flipped to tails flipped. If this is correct, then the ratio would be 24 to 8. My reasoning for this is, it already tells you that you have 8 times that tails was flipped, and all you have to do to figure out the amount of times heads if flipped it to subtract: 32-8=24, so that means that heads was flipped a total of 24 times. The last thing that you have to do is to put it into a ratio, and in the order it gives you initially, which would make the answer (3 ways):

1)   24 to 8
2)   24 : 8
3)   24/8

I hope this helps you.
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Hii please help me!!!!!
inysia [295]
It should be eight if I remember correctly
3 0
2 years ago
Read 2 more answers
If cos(x)=1/4 what is sin(x) and tan(x)
anygoal [31]
You can use the identity
  cos(x)² +sin(x)² = 1
to find sin(x) from cos(x) or vice versa.

  (1/4)² +sin(x)² = 1
  sin(x)² = 1 - 1/16
  sin(x) = ±(√15)/4


Then the tangent can be computed as the ratio of sine to cosine.
  tan(x) = sin(x)/cos(x) = (±(√15)/4)/(1/4)
  tan(x) = ±√15


There are two possible answers.
In the first quadrant:
  sin(x) = (√15)/4
  tan(x) = √15

In the fourth quadrant:
  sin(x) = -(√15)/4
  tan(x) = -√15
3 0
3 years ago
1. Find the lengths of the missing sides in the pairs of s 5 X 4 2 3 7​
Ahat [919]

Answer:

21185

Step-by-step explanation:

7 0
2 years ago
Algebra 2 - Grade 11
saveliy_v [14]

Answer:

for the first equation

f(-3) = 34

f(4) = 6

for the 2nd equation

f(-3) = -56

f(4) ÷ 70

Step-by-step explanation:

my work is attached in a picture.

all you do is substitute each x value into each equation

8 0
2 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
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