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2 years ago

Parents wish to have $160,000 available for a child's education. If the child is now

1 answer:

4 0

A=p (1+I/k)^kn

A future value 160000
p present value ?
I interest rate 6/100=0.06
K compounded semiannual 2
T time 18-7=11years

160000=p (1+0.06/2)^(2×11)
Divide each side by (1+0.06/2)^(2×11)
P=160,000÷(1+0.06÷2)^(2×11)
P=83,502.8

Hope it helps:-)

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Bradley and his family drove to visit a museum. They drove 9/25 of the way and stopped for gasoline. Write the fraction of the d

labwork [276]

The answer is 0.36.

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2 years ago

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Which solid does this net form?

polet [3.4K]

Answer:

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Step-by-step explanation:

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1 year ago

The distance between two points is 6_/6.One endpoint is (4,-1). It is known that the y-coordinate of the other endpoint is 9.

babunello [35]

The x-coordinate of the given endpoint will be " $x = 4 \pm 2\sqrt{29}$ ".

According to the question,

The end points are:

$(x_1,y_1) = (4,-1)$
$(x_2, y_2) = (x,9)$

Distance,

$6\sqrt{6}$

As we know,

The distance formula,

→ $Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

By substituting the values, we get

→ $6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}$

→ $216= (x-4)^2+100$

→ $(x-4)^2 = 116$

→ $x-4 = \pm \sqrt{116}$

→ $x-4=\pm 2\sqrt{29}$

→ $x = 4 \pm 2\sqrt{29}$

Thus the above answer is right.

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brainly.com/question/18310956

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2 years ago

A rectangle has a length of 45 inches less than 4 times its width. if the area of the rectangle is 3325 square inches, find the

Maru [420]

The length of the rectangle is based on its width, so let's call width w and put the length in terms of the width. We are told that the width is 45 less than 4 times the width, so the length is 4w - 45. Area is found by multiplying length times width and we are given the area as 3325. So we will set up length times width and solve for w, which we will then use to solve for l. 3325 = (4w - 45)(w). Multiplying out we have $3325=4w^2-45w$ . Move the constant over by subtraction and then we will have a quadratic that can be factored to solve for w. $4w^2-45w-3325=0$ . We would put that through the quadratic formula to solve for w. When we do that we get that w = 35 and w = -23.75. The 2 things in math that will never EVER be negative is time and distance/length, so -23.75 is out. That means that the width is 35. The length is 4(35) - 45 which is 95. The dimensions of your rectangle are length is 95 and width is 35. There you go!