SA=(a+b+c) h+bh
=(5+12+13)*4+5*12
=20*4+60
=80+60
=140 cm squared
Let Surface Area A, a the base edge and h the height:
A = a²+2a√(a²/4+h²)
h=?
pythagorean theorem:
h²=c²-a²
h=√(c²-a²)
h=√(8²-(.7/2)²)= 8
plug it in the above equation A= 11.7ft²
So A is correct
4 consecutive integers : (x), (x + 1), (x + 2), (x + 3)
x + x + 1 + x + 2 + x + 3 = 114...combine like terms
4x + 6 = 114....subtract 6 from both sides
4x = 114 - 6
4x = 108...divide both sides by 4
x = 108/4
x = 27
x + 1 = 27 + 1 = 28
x + 2 = 27 + 2 = 29
x + 3 = 27 + 3 = 30
so ur 4 numbers are : 27, 28, 29, 30
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2