Answer:
I count 10 triangles.....
Answer: option C is the correct answer
Step-by-step explanation:
The system of linear equations is
10x + 7y = 12 - - - - - - - 1
8x + 7y = 18 - - - - - - - 2
Since the coefficient of y is the same in equation 1 and equation 2, we will eliminate y by subtracting equation 2 from equation 1, it becomes
10x - 8x + 7y - 7y = 12 - 18
2x = -6
x = - 6/2 = - 3
Substituting x = - 3 into equation 1, it becomes
10×-3 + 7y = 12
-30 + 7y = 12
Let the constants be on the right hand side and the term containing y be on the left hand side. It becomes
7y = 12 + 30
7y = 42
y = 42/7
y = 6
C) (−3, 6)
Answer: it will take 14 years
Step-by-step explanation:
A savings account is started with an initial deposit of $600. This means that the principal P is
P = 600
It was compounded annually. This means that it was compounded once in a year. Therefore,
n = 1
The rate at which the principal was compounded is 2.1%. So
r = 2.1/100 = 0.021
The duration of time that for which the money stayed in the account is t years. So
Time = t
The formula for compound interest is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years. Therefore,
a) the equation to represent the amount of money in the account as a function of time in years would be
A = 600 (1+0.021/1)^1×t
A = 600 (1.021)^t
b) the amount of time it takes for the account balance to reach $800 would be
800 = 600 (1.021)^t
Dividing both sides of the equation by 600, it becomes
1.33 = (1.021)^t
t = 14
Answer:
degree 5, leading coefficient 1
Step-by-step explanation:
When the sign of the end behavior matches that of x, the leading coefficient is positive, and the degree is odd.
One possibility is ...
degree 5, leading coefficient 1
Answer: 
Step-by-step explanation:
If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:
![\sqrt[7]{x^{2} } = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} } = (x^{3} )^{1/5} = (x^{\frac{3}{5}})](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B2%7D%20%7D%20%20%3D%20%28x%5E%7B2%7D%20%29%5E%7B1%2F7%7D%20%3D%20%28x%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%29%5C%5C%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%20%7D%20%20%3D%20%28x%5E%7B3%7D%20%29%5E%7B1%2F5%7D%20%3D%20%28x%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%29)
And multiply:
