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Vikki [24]
3 years ago
8

A random sample of 10 employees for the Department of Health and Human Services has the following salaries in thousands of dolla

rs. Assuming normality, use a TI-83, TI-83 plus, or TI-84 calculator to find the 98% confidence interval for the true population mean salary. Round your answers to two decimal places and use increasing order. Salary
72
71
66
71
69
71
72
69
70
71
Mathematics
1 answer:
julsineya [31]3 years ago
6 0

Answer:

(68.58,71.82)

Step-by-step explanation:

You might be interested in
Which function has a range of y&lt;3?<br> y=3(2)<br> y=2(3)<br> O y=-(2)* +3<br> O y= (2)* - 3
VARVARA [1.3K]

option C is correct.

<u>Step-by-step explanation:</u>

If a function is defined as

f(x)=a^x where, a>0, then the range of the function is greater than 0.

a^x>0               .... (1)

Option A: Using inequity (1),

2^x>0

Multiply both side by 3.

3(2^x)>0

The range of first function is y>0. Therefore option A is incorrect.

Option B: Using inequity (1),

3^x>0

Multiply both side by 2.

2(3^x)>0

The range of second function is y>0. Therefore option B is incorrect.

Option C: Using inequity (1),

2^x>0

Multiply both side by -1.

-2^x

Add 3 on both the sides.

-2^x+3

y

The range of first function is y<3. Therefore option C is correct.

Option D: Using inequity (1),

2^x>0

Subtract 3 from both the sides.

2^x-3>-3

y>-3

The range of second function is y>-3. Therefore option D is incorrect.

7 0
3 years ago
My question is in the picture pls help
pentagon [3]

Answer:

A. 8cm

Step-by-step explanation:

3 times 2 is 6. 22-6 is 16. 16/2 is 8

8 0
3 years ago
2. A 2-pint bottle of olive oil costs $2.68. If
tino4ka555 [31]

Answer:

21.44 All you need to do is divide the 2.68 by 2 then multiply it by 16

7 0
3 years ago
What is the unit value of 3 in 432?
vaieri [72.5K]
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6 0
3 years ago
Read 2 more answers
A fast-food company is interested in knowing the probability of whether a customer viewed an advertisement for their new special
lord [1]

Answer:

45% probability that a randomly selected customer saw the advertisement on the internet or on television

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a customer saw the advertisement on the internet.

B is the probability that a customer saw the advertisement on television.

We have that:

A = a + (A \cap B)

In which a is the probability that a customer saw the advertisement on the internet but not on television and A \cap B is the probability that the customers saw the advertisement in both the internet and on television.

By the same logic, we have that:

B = b + (A \cap B)

12% saw it on both the internet and on television.

This means that A \cap B = 0.12

20% saw it on television

This means that B = 0.2

37% of customers saw the advertisement on the internet

This means that A = 0.37

What is the probability that a randomly selected customer saw the advertisement on the internet or on television

A \cup B = A + B - (A \cap B) = 0.37 + 0.2 - 0.12 = 0.45

45% probability that a randomly selected customer saw the advertisement on the internet or on television

6 0
3 years ago
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