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Semenov [28]
3 years ago
11

[(5^2)^2]^2how to do this​

Mathematics
2 answers:
pshichka [43]3 years ago
6 0
Really simple 5^2^2 is equal to 5^4 because a power raised to a power multiple
Your answer is 5^8
Lana71 [14]3 years ago
4 0

Step-by-step explanation:

  • {(5^2)^2}^2
  • (5^4)^2
  • 5^8
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AB = BC = AC
IgorLugansk [536]

Answer:

  45 cubic units

Step-by-step explanation:

See attached.

3 0
3 years ago
WILL GIVE A BRAINLIEST
skelet666 [1.2K]
Find slope
slope betwen 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

so
first make denoms same
denom is 10
(4/5,1/5) turns to (8/10,2/10)
(1/2,3/2) turns to (5/10,15/10)
slope=(15/10-2/10)/(5/10-8/10)=(13/10)/(-3/10)=13/-3=-13/3

use point slope
use (4/5,1/5)
y-y1=m(x-x1)
a point is (x1,y1) and slope is m
y-1/5=-13/3(x-4/5)
expand
wait, we don't need to do that, the only one with slope -13/3 is D
answer is D
4 0
3 years ago
What is the equation of a circle whose center is at the origin and contains the point (7, 0)?
oksano4ka [1.4K]
(x-center)^2+(y-center)^2=r^2
x^2+y^2=r^2
(7)^2+(0)^2=r^2
49+0=r^2
r^2=49, r=7
x^2+y^2=49
7 0
3 years ago
I need some help on this one
Gennadij [26K]

Answer:

3°

Step-by-step explanation:

5 0
2 years ago
Solve the system of equations: y²-x²=16, x²-y²=16 (explain and show work) Will name most brainy
mr Goodwill [35]
<h3>Answer: No solutions (system is inconsistent)</h3>

=====================================================

Explanation:

Rearrange the first equation into -x^2+y^2 = 16

So we have this equivalent system

\begin{cases}-x^2+y^2 = 16\\\\x^2-y^2=16\end{cases}

If you add the terms straight down, then you'll find that the x^2 and y^2 terms add to 0. The right hand side terms add to 16+16 = 32

We are left with the equation 0 = 32, which is a false equation or contradiction. Therefore, there are no solutions. We say the system is inconsistent. The two graphs do not intersect at all as shown in the diagram below. We have two hyperbolas in which the branches extend off to infinity to slowly approach the asymptotes. They never actually get to the asymptotes, but only get closer.

7 0
3 years ago
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