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2 years ago

PLS ASAP I NEED HELP PLS HELP HELP ANSWER THE QEUSTION IN THE PHOTO

Mathematics

1 answer:

ddd [48]2 years ago

8 0

Answer:

Step-by-step explanation:

if BU and BN weren't congruent, then the two triangles couldn't be proved to be congruent

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Hardy was given the scale drawing of the enlargement to Analyze Hardy's work to determine if he is correct. If he

irakobra [83]

Answer:

the correct answer is NO. hardy should have multiplied by the scale factor to find the missing length.

Step-by-step explanation:

dont got one hehehe

8 0

3 years ago

Read 2 more answers

Solve 3/5=8/y. Round to the nearest tenth. 15.2 9.8 13.3 18.8

Sidana [21]

3/5 = 3/y
40 = 3y
Divide both by 3
Answer= 13.3

4 0

3 years ago

Determine where to place the decimal point in the dividend and divisor so that the quotient is between 23 and 25

timama [110]

Answer:

Place the decimal before the last digit in both number i.e. 1602.3 and 65.4

Step-by-step explanation:

We are given the numerical expression 16023÷654.

Here, we have,

Dividend = 16023

Divisor = 654

it is required that the quotient of the division to be between 23 and 25.

If we take the numbers,

1602.3 and 65.4

This gives us,

$\frac{1602.3}{65.4}=24.5$ .

Hence, placing the decimal before the last digit in both number will give the desired result.

7 0

3 years ago

Which mixed number is equivalent to 708/100

Brut [27]

Hello there!

The correct answer is 7 $\frac{8}{100}$ .

Hope This Helps You!
Good Luck :)

3 0

3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .

We have to find M.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 2.81\sqrt{\frac{0.12*0.88}{5615}}$

$M = 0.012$

7 0

3 years ago