24ft is the hypotenuse, at an angle of 75<span>⁰, and we need to find the adjacent.
We use cos(), which is adjacent divided by hypotenuse.
Therefore, we can find the adjacent by doing:
25 * cos(75) = 6.47ft
Round the answer however you like.</span>
Answer: 24
A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.
the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.
The general equation for the vertical hyperbola is
[ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1
The conjugate axis of the vertical hyperbola is y = k
Length of the conjugate axis = 2b
According to the question k = 2, h = -1, a = 4, b = 12
Length of the conjugate axis = 2b = 2 * 12 = 24
Learn more about hyperbola here :
brainly.com/question/3351710
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Answer:
Student B did the problem corectly
Step-by-step explanation:
Student a did 3*4 while student B did 3*3*3*3 which would equal 27
Answer:
(-16.494 ; -3.506)
Step-by-step explanation:
student Prob A Prob B difference, d (A-B)
1 20 35____ - 15
2 30 40 ___ - 10
3 15 20 ___ - 5
4 40 50 __ - 10
Difference, d = -15, -10, -5, -10
Xd = Σd/ n = - 40 / 4 = - 10
Standard deviation of d ; Sd = 4.082
The confidence interval for the difference is given as :
Xd ± Tcritical*(Sd/√n)
Tcritical at 95%; df = n - 1 ; 4 - 1 = 3
Tcritical(0.05, 3)). = 3.182
C.I = -10 ± 3.182(4.082/√4)
C.I = -10 ± 6.494462
C. I = (-16.494 ; -3.506)
Imagine the coordinates as x and y. So if you go out to 2 on the x axis, and up 0 you have one dot. Now go out 2 on the x axis, and up 5 on the y axis. The two dots when connected are vertical. I believe you are correct.